x^2-10x+40=8

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Solution for x^2-10x+40=8 equation:


Simplifying
x2 + -10x + 40 = 8

Reorder the terms:
40 + -10x + x2 = 8

Solving
40 + -10x + x2 = 8

Solving for variable 'x'.

Reorder the terms:
40 + -8 + -10x + x2 = 8 + -8

Combine like terms: 40 + -8 = 32
32 + -10x + x2 = 8 + -8

Combine like terms: 8 + -8 = 0
32 + -10x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-32' to each side of the equation.
32 + -10x + -32 + x2 = 0 + -32

Reorder the terms:
32 + -32 + -10x + x2 = 0 + -32

Combine like terms: 32 + -32 = 0
0 + -10x + x2 = 0 + -32
-10x + x2 = 0 + -32

Combine like terms: 0 + -32 = -32
-10x + x2 = -32

The x term is -10x.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x + 25 + x2 = -32 + 25

Reorder the terms:
25 + -10x + x2 = -32 + 25

Combine like terms: -32 + 25 = -7
25 + -10x + x2 = -7

Factor a perfect square on the left side:
(x + -5)(x + -5) = -7

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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